What is the solution for (dy)/(dx)=10^{x+y} ?

The solution for (dy)/(dx)=10^{x+y} is y=-(ln(-10^x-c_{1}))/(ln(10))

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(dy)/(dx)=10^{x+y}

\frac{d y}{d x} = 1 0^{x + y}

y = - \frac{ln ( - 1 0 ^{x} - c _{1} )}{ln ( 10 )}

Solution steps

\frac{d y}{d x} = 1 0^{x + y}

Solve separable ODE:

y = - \frac{ln ( - 1 0 ^{x} - c _{1} )}{ln ( 10 )}

y = - \frac{ln ( - 1 0 ^{x} - c _{1} )}{ln ( 10 )}

\frac{d}{d x} (x (s - 2 x) (s - 2 x))

n = 0 \sum \infty n^{\frac{3}{2}}

n = 3 \sum \infty (\frac{6}{11})^{- n}

4 x (x^{2} - 9)

What is the solution for (dy)/(dx)=10^{x+y} ?
The solution for (dy)/(dx)=10^{x+y} is y=-(ln(-10^x-c_{1}))/(ln(10))