What is the solution for xy^'+y=-9xy^2,y(1)=-2 ?

The solution for xy^'+y=-9xy^2,y(1)=-2 is y= 2/(x(18ln(x)-1))

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xy^'+y=-9xy^2,y(1)=-2

x y^{^{'}} + y = - 9 x y^{2}, y (1) = - 2

y = \frac{2}{x ( 18 ln ( x ) - 1 )}

Solution steps

x y^{'} (x) + y = - 9 x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( 18 ln ( x ) - 1 )}

y = \frac{2}{x ( 18 ln ( x ) - 1 )}

x \to x + 2 lim (2 x^{2} + 3 x - 2)

(\frac{sin ( x )}{x})^{^{'}}

f (x) = ln (3 + 4 x)

\frac{S}{( ( S ^{2} + 9 ) ^{2} )}

\int 3 e^{3 x} sin (e^{3 x}) d x

What is the solution for xy^'+y=-9xy^2,y(1)=-2 ?
The solution for xy^'+y=-9xy^2,y(1)=-2 is y= 2/(x(18ln(x)-1))