What is the derivative of sin^2(2bx) ?

The derivative of sin^2(2bx) is 4bsin(2bx)cos(2bx)

What is the first derivative of sin^2(2bx) ?

The first derivative of sin^2(2bx) is 4bsin(2bx)cos(2bx)

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\frac{d}{d x} (sin^{2} (2 b x))

4 b sin (2 b x) cos (2 b x)

Solution steps

\frac{d}{d x} (sin^{2} (2 b x))

Apply the chain rule:

2 sin (2 b x) \frac{d}{d x} (sin (2 b x))

= 2 sin (2 b x) \frac{d}{d x} (sin (2 b x))

\frac{d}{d x} (sin (2 b x)) = cos (2 b x) \cdot 2 b

= 2 sin (2 b x) cos (2 b x) \cdot 2 b

Simplify

= 4 b sin (2 b x) cos (2 b x)

\int \frac{6 + x + x ^{2}}{x} d x

\frac{d x}{d t} = - 3 x + 6 e^{- t}

\frac{d}{d x} (x^{3} - 4 x^{2} + 45 x + 10)

\int_{0}^{5} x e^{- 2 x} d x

y^{^{'}} = e^{4 x} - 6 x

What is the derivative of sin^2(2bx) ?
The derivative of sin^2(2bx) is 4bsin(2bx)cos(2bx)
What is the first derivative of sin^2(2bx) ?
The first derivative of sin^2(2bx) is 4bsin(2bx)cos(2bx)