What is the solution for (dx)/(dt)=-3x+6e^{-t} ?

The solution for (dx)/(dt)=-3x+6e^{-t} is x= 3/(e^t)+(c_{1})/(e^{3t)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dt)=-3x+6e^{-t}

\frac{d x}{d t} = - 3 x + 6 e^{- t}

x = \frac{3}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

Solution steps

\frac{d x}{d t} = - 3 x + 6 e^{- t}

Solve linear ODE:

x = \frac{3}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

x = \frac{3}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

\frac{d}{d x} (x^{3} - 4 x^{2} + 45 x + 10)

\int_{0}^{5} x e^{- 2 x} d x

y^{^{'}} = e^{4 x} - 6 x

x \to 0 lim (\frac{- 6}{e ^{3} - x})

\frac{8 s ^{2} + 12 s + 7}{s ^{2} + s}

What is the solution for (dx)/(dt)=-3x+6e^{-t} ?
The solution for (dx)/(dt)=-3x+6e^{-t} is x= 3/(e^t)+(c_{1})/(e^{3t)}