What is the derivative of-sqrt(x+1) ?

The derivative of-sqrt(x+1) is -1/(2sqrt(x+1))

What is the first derivative of-sqrt(x+1) ?

The first derivative of-sqrt(x+1) is -1/(2sqrt(x+1))

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\frac{d}{d x} (- x + 1)

- \frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (- x + 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (x + 1)

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - \frac{1}{2 x + 1} \cdot 1

Simplify

= - \frac{1}{2 x + 1}

\int \frac{1}{tan ( x ) sec ( x )} d x

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\int_{- 1}^{1} - x^{2} + 1 d x

\frac{\partial}{\partial y} (x^{5} y^{10} cos (x y^{2}))

\frac{d}{d x} (∣ 2 x - 3 ∣)

What is the derivative of-sqrt(x+1) ?
The derivative of-sqrt(x+1) is -1/(2sqrt(x+1))
What is the first derivative of-sqrt(x+1) ?
The first derivative of-sqrt(x+1) is -1/(2sqrt(x+1))