What is the derivative of f(x)=sin^3(3x) ?

The derivative of f(x)=sin^3(3x) is 9sin^2(3x)cos(3x)

What is the first derivative of f(x)=sin^3(3x) ?

The first derivative of f(x)=sin^3(3x) is 9sin^2(3x)cos(3x)

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derivative of

f (x) = sin^{3} (3 x)

9 sin^{2} (3 x) cos (3 x)

Solution steps

\frac{d}{d x} (sin^{3} (3 x))

Apply the chain rule:

3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

= 3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 3 (sin (3 x))^{2} cos (3 x) \cdot 3

Simplify

= 9 sin^{2} (3 x) cos (3 x)

y^{^{'}} + 10 y = 4

\int 25 sin^{2} (x) d x

7 x - 7 x

x \to 9 lim (1 - 4 x^{3})

\frac{1}{20 x ^{2}}, x, \frac{x}{20}

What is the derivative of f(x)=sin^3(3x) ?
The derivative of f(x)=sin^3(3x) is 9sin^2(3x)cos(3x)
What is the first derivative of f(x)=sin^3(3x) ?
The first derivative of f(x)=sin^3(3x) is 9sin^2(3x)cos(3x)