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Popular >

integral from 1 to 2 of (2x+x^2)

Solution

\int_{1}^{2} (2 x + x^{2}) d x

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

\int_{1}^{2} 2 x + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} x^{2} d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} x^{2} d x = \frac{7}{3}

= 3 + \frac{7}{3}

Simplify

3 + \frac{7}{3} : \frac{16}{3}

= \frac{16}{3}

Popular Examples

integral of (1/(1-x^2))

\int (\frac{1}{1 - x ^{2}}) d x

xy^2(dy)/(dx)=y^3+x^3,y(1)=5

x y^{2} \frac{d y}{d x} = y^{3} + x^{3}, y (1) = 5

(\partial)/(\partial x)((2x)/(x-y))

\frac{\partial}{\partial x} (\frac{2 x}{x - y})

5t*(dy)/(dt)+2y=sqrt(t)

5 t \cdot \frac{d y}{d t} + 2 y = t

derivative of y^{3/2}(y+ce^y)derivative of

y^{\frac{3}{2}} (y + c e^{y})

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x+x^2) ?
The integral from 1 to 2 of (2x+x^2) is 16/3