What is the derivative of 8/(t^8)-6/(t^6)+3/t ?

The derivative of 8/(t^8)-6/(t^6)+3/t is -(64)/(t^9)+(36)/(t^7)-3/(t^2)

What is the first derivative of 8/(t^8)-6/(t^6)+3/t ?

The first derivative of 8/(t^8)-6/(t^6)+3/t is -(64)/(t^9)+(36)/(t^7)-3/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{8}{t ^{8}} - \frac{6}{t ^{6}} + \frac{3}{t}

- \frac{64}{t ^{9}} + \frac{36}{t ^{7}} - \frac{3}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{8}{t ^{8}} - \frac{6}{t ^{6}} + \frac{3}{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{8}{t ^{8}}) - \frac{d}{d t} (\frac{6}{t ^{6}}) + \frac{d}{d t} (\frac{3}{t})

\frac{d}{d t} (\frac{8}{t ^{8}}) = - \frac{64}{t ^{9}}

\frac{d}{d t} (\frac{6}{t ^{6}}) = - \frac{36}{t ^{7}}

\frac{d}{d t} (\frac{3}{t}) = - \frac{3}{t ^{2}}

= - \frac{64}{t ^{9}} - (- \frac{36}{t ^{7}}) - \frac{3}{t ^{2}}

Simplify

= - \frac{64}{t ^{9}} + \frac{36}{t ^{7}} - \frac{3}{t ^{2}}

f (x) = arctan (sin (4 x))

\int \frac{1}{x ^{2} + 2 x + 82} d x

\int (2 x - \frac{3}{x}) d x

\int_{1}^{e^{2}} x^{5} ln (x) d x

\int x y e^{x y^{2}} d y

What is the derivative of 8/(t^8)-6/(t^6)+3/t ?
The derivative of 8/(t^8)-6/(t^6)+3/t is -(64)/(t^9)+(36)/(t^7)-3/(t^2)
What is the first derivative of 8/(t^8)-6/(t^6)+3/t ?
The first derivative of 8/(t^8)-6/(t^6)+3/t is -(64)/(t^9)+(36)/(t^7)-3/(t^2)