What is the sum from n=1 to infinity of 4n-1 ?

The sum from n=1 to infinity of 4n-1 is diverges

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sum from n=1 to infinity of 4n-1

n = 1 \sum \infty 4 n - 1

diverges

Solution steps

n = 1 \sum \infty 4 n - 1

Apply Series Divergence Test:

diverges

= diverges

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\frac{d}{d x} (\frac{3 x}{s q u ( x , q ) a r ( x , q ) e x ^{2} + 1})

x \to 1 lim (\frac{1}{x ^{3}})

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\int \frac{6}{x ^{2} + 16} d x

What is the sum from n=1 to infinity of 4n-1 ?
The sum from n=1 to infinity of 4n-1 is diverges