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Popular >

area x^2,4,[0,2]

Solution

area

x^{2}, 4, [0, 2]

Solution

\frac{64}{3} + (\frac{( 0 , 2 ) ^{3}}{3} - \frac{64}{3})

Solution steps

Apply the area formula:

\int_{4}^{[0, 2]} ∣ x ∣^{2} d x

Solve

\int_{4}^{[0, 2]} ∣ x ∣^{2} d x : \frac{64}{3} + (\frac{( 0 , 2 ) ^{3}}{3} - \frac{64}{3})

The area is:

= \frac{64}{3} + (\frac{( 0 , 2 ) ^{3}}{3} - \frac{64}{3})

Popular Examples

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\int_{0}^{4} \frac{1}{16 + t ^{2}} d t

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\frac{d}{d x} (x^{2} + \frac{1}{x ^{2}})

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n = 0 \sum \infty \frac{7 ^{n}}{6 ^{n}}

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\int 8 x (4 x^{2} - 3)^{5} d x

integral of 1/((x+5)^2(x-1))

\int \frac{1}{( x + 5 ) ^{2} ( x - 1 )} d x

Frequently Asked Questions (FAQ)

What is area x^2,4,[0,2] ?
The answer to area x^2,4,[0,2] is 64/3+(((0,2)^3)/3-64/3)