What is the integral of (e^{x^2})^2 ?

The integral of (e^{x^2})^2 is (sqrt(pi))/(2sqrt(2))\erfi(sqrt(2)x)+C

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integral of (e^{x^2})^2

\int (e^{x^{2}})^{2} d x

\frac{π}{2 2} erfi (2 x) + C

Solution steps

\int (e^{x^{2}})^{2} d x

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= \int e^{2 x^{2}} d x

= \int e^{(2 x)^{2}} d x

Apply u-substitution

: \int e^{u^{2}} \frac{1}{2} d u

= \int e^{u^{2}} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u^{2}} d u

Use the nonelementary integral:

\int e^{u^{2}} d u = \frac{π}{2} erfi (u)

= \frac{1}{2} \cdot \frac{π}{2} erfi (u)

Substitute back

u = 2 x

= \frac{1}{2} \cdot \frac{π}{2} erfi (2 x)

Simplify

\frac{1}{2} \cdot \frac{π}{2} erfi (2 x) : \frac{π}{2 2} erfi (2 x)

= \frac{π}{2 2} erfi (2 x)

Add a constant to the solution

= \frac{π}{2 2} erfi (2 x) + C

\frac{d}{d x} ((3 x + 5)^{3})

x \to 4 lim (3 x)

x^{2}, 0, 4

cos (\frac{1 - e ^{5 x}}{1 + e ^{5 x}})

\frac{\partial}{\partial x} (ln (\frac{( 2 x - 1 )}{x - 1}))

What is the integral of (e^{x^2})^2 ?
The integral of (e^{x^2})^2 is (sqrt(pi))/(2sqrt(2))\erfi(sqrt(2)x)+C