What is (\partial)/(\partial z)(3xsin(y-z)) ?

The answer to (\partial)/(\partial z)(3xsin(y-z)) is -3xcos(y-z)

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(\partial)/(\partial z)(3xsin(y-z))

\frac{\partial}{\partial z} (3 x sin (y - z))

- 3 x cos (y - z)

Solution steps

\frac{\partial}{\partial z} (3 x sin (y - z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x \frac{\partial}{\partial z} (sin (y - z))

Apply the chain rule:

cos (y - z) \frac{\partial}{\partial z} (y - z)

= cos (y - z) \frac{\partial}{\partial z} (y - z)

\frac{\partial}{\partial z} (y - z) = - 1

= 3 x cos (y - z) (- 1)

Simplify

= - 3 x cos (y - z)

y^{^{''}} + 5 y^{^{'}} - 14 y = e^{(4 x)}

(- 1.2) (3.3)

\frac{\partial}{\partial x} (\frac{e ^{x}}{y})

x \to 0 lim ((1 + a x)^{\frac{b}{x}})

\frac{d}{d x} (\frac{9 - x ^{2}}{16 x})

What is (\partial)/(\partial z)(3xsin(y-z)) ?
The answer to (\partial)/(\partial z)(3xsin(y-z)) is -3xcos(y-z)