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Popular >

y^'=x+y,y(0)=6

Solution

y^{^{'}} = x + y, y (0) = 6

Solution

y = - x - 1 + 7 e^{x}

Solution steps

y^{'} (x) = x + y

Solve linear ODE:

y = - x - 1 + 7 e^{x}

y = - x - 1 + 7 e^{x}

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\int_{0}^{3} 5 - x^{2} d x

laplacetransform 2tcos(2t)laplace transform

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derivative of 7x+6

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x+y,y(0)=6 ?
The solution for y^'=x+y,y(0)=6 is y=-x-1+7e^x