What is (\partial)/(\partial x)(10y+x-z(xy-121)) ?

The answer to (\partial)/(\partial x)(10y+x-z(xy-121)) is -yz+1

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(\partial)/(\partial x)(10y+x-z(xy-121))

\frac{\partial}{\partial x} (10 y + x - z (x y - 121))

- yz + 1

Solution steps

\frac{\partial}{\partial x} (10 y + x - z (x y - 121))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (10 y) + \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (z (x y - 121))

\frac{\partial}{\partial x} (10 y) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (z (x y - 121)) = yz

= 0 + 1 - yz

Simplify

= - yz + 1

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What is (\partial)/(\partial x)(10y+x-z(xy-121)) ?
The answer to (\partial)/(\partial x)(10y+x-z(xy-121)) is -yz+1