What is the derivative of f(x)= 6/(5x+3) ?

The derivative of f(x)= 6/(5x+3) is -(30)/((5x+3)^2)

What is the first derivative of f(x)= 6/(5x+3) ?

The first derivative of f(x)= 6/(5x+3) is -(30)/((5x+3)^2)

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derivative of

f (x) = \frac{6}{5 x + 3}

- \frac{30}{( 5 x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6}{5 x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{5 x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((5 x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 5 x + 3 ) ^{2}} \frac{d}{d x} (5 x + 3)

= - \frac{1}{( 5 x + 3 ) ^{2}} \frac{d}{d x} (5 x + 3)

\frac{d}{d x} (5 x + 3) = 5

= 6 (- \frac{1}{( 5 x + 3 ) ^{2}} \cdot 5)

Simplify

6 (- \frac{1}{( 5 x + 3 ) ^{2}} \cdot 5) : - \frac{30}{( 5 x + 3 ) ^{2}}

= - \frac{30}{( 5 x + 3 ) ^{2}}

\int_{0}^{2 π} e^{i x} d x

\frac{2 x}{x + 1}, at x = 1

\frac{1}{s ^{2} ( s ^{2} + 2 s + 3 )}

\int x^{6} e^{- 4 x} d x

\int_{0}^{1} \frac{6}{x ^{2} + 1} d x

What is the derivative of f(x)= 6/(5x+3) ?
The derivative of f(x)= 6/(5x+3) is -(30)/((5x+3)^2)
What is the first derivative of f(x)= 6/(5x+3) ?
The first derivative of f(x)= 6/(5x+3) is -(30)/((5x+3)^2)