What is (\partial)/(\partial y)(e^{-y}-2x) ?

The answer to (\partial)/(\partial y)(e^{-y}-2x) is -e^{-y}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(e^{-y}-2x)

\frac{\partial}{\partial y} (e^{- y} - 2 x)

- e^{- y}

Solution steps

\frac{\partial}{\partial y} (e^{- y} - 2 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{- y}) - \frac{\partial}{\partial y} (2 x)

\frac{\partial}{\partial y} (e^{- y}) = - e^{- y}

\frac{\partial}{\partial y} (2 x) = 0

= - e^{- y} - 0

Simplify

= - e^{- y}

\int (- 12 x - 1) - 6 x^{2} - x + 1 d x

\int \frac{t}{t ^{4} + 5} d t

8 sin (3 t) + 2 cos (2 t)

\int \frac{e ^{s i n (x)}}{sec ( x )} d x

f (x) = (3 x^{3} + 5) (x^{4} - 5 x)

What is (\partial)/(\partial y)(e^{-y}-2x) ?
The answer to (\partial)/(\partial y)(e^{-y}-2x) is -e^{-y}