What is (\partial)/(\partial y)(4x-2y) ?

The answer to (\partial)/(\partial y)(4x-2y) is -2

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(\partial)/(\partial y)(4x-2y)

\frac{\partial}{\partial y} (4 x - 2 y)

- 2

Solution steps

\frac{\partial}{\partial y} (4 x - 2 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (4 x) = 0

\frac{\partial}{\partial y} (2 y) = 2

= 0 - 2

Simplify

= - 2

\int 4 + \frac{1}{x} d x

\frac{d}{d x} (20 x - \frac{1}{2} \cdot 9.8 \cdot x^{2})

\int 2 sin^{3} (x) cos^{2} (x) d x

\frac{d y}{d t} = \frac{2 t + sec ^{2} ( t )}{2 y}

What is (\partial)/(\partial y)(4x-2y) ?
The answer to (\partial)/(\partial y)(4x-2y) is -2