What is the solution for y^{''}-y=5sin(2ty)(0) ?

The solution for y^{''}-y=5sin(2ty)(0) is y=c_{1}e^t+c_{2}e^{-t}

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y^{''}-y=5sin(2ty)(0)

y^{^{''}} - y = 5 sin (2 t y) (0)

y = c_{1} e^{t} + c_{2} e^{- t}

Solution steps

y^{''} (t) - y = 5 sin (2 t y) (0)

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t}

y = c_{1} e^{t} + c_{2} e^{- t}

\frac{d}{d x} (sin (x) + sin^{2} (x))

(0, 4), (6, - 4)

\frac{d y}{d x} = x y^{3} - x y

x \to - 2 lim (9 - x)

What is the solution for y^{''}-y=5sin(2ty)(0) ?
The solution for y^{''}-y=5sin(2ty)(0) is y=c_{1}e^t+c_{2}e^{-t}