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Popular >

y^'=ycos(2x)

Solution

y^{^{'}} = y cos (2 x)

Solution

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

Solution steps

y^{'} (x) = y cos (2 x)

Solve separable ODE:

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

Popular Examples

integral from 1 to infinity of xe^{-x^2}

\int_{1}^{\infty} x e^{- x^{2}} d x

y(2xy+1)dx-xdy=0

y (2 x y + 1) d x - x d y = 0

derivative of sin(3x)+cos(3x)derivative of

sin (3 x) + cos (3 x)

integral of 2/(x^2+x-2)

\int \frac{2}{x ^{2} + x - 2} d x

integral of (e^{bx}*x)

\int (e^{b x} \cdot x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=ycos(2x) ?
The solution for y^'=ycos(2x) is y=e^{1/2 sin(2x)+c_{1}}