What is the integral of sin(4x)sin(nx) ?

The integral of sin(4x)sin(nx) is 1/2 (-1/(4+n)sin(4x+nx)+1/(4-n)sin(4x-nx))+C

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integral of sin(4x)sin(nx)

\int sin (4 x) sin (n x) d x

\frac{1}{2} (- \frac{1}{4 + n} sin (4 x + n x) + \frac{1}{4 - n} sin (4 x - n x)) + C

Solution steps

\int sin (4 x) sin (n x) d x

Rewrite using trig identities

= \int \frac{- cos ( 4 x + n x ) + cos ( 4 x - n x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int - cos (4 x + n x) + cos (4 x - n x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (- \int cos (4 x + n x) d x + \int cos (4 x - n x) d x)

\int cos (4 x + n x) d x = \frac{1}{4 + n} sin (4 x + n x)

\int cos (4 x - n x) d x = \frac{1}{4 - n} sin (4 x - n x)

= \frac{1}{2} (- \frac{1}{4 + n} sin (4 x + n x) + \frac{1}{4 - n} sin (4 x - n x))

Add a constant to the solution

= \frac{1}{2} (- \frac{1}{4 + n} sin (4 x + n x) + \frac{1}{4 - n} sin (4 x - n x)) + C

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x \to \infty lim ((0.6)^{\frac{1}{x}})

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What is the integral of sin(4x)sin(nx) ?
The integral of sin(4x)sin(nx) is 1/2 (-1/(4+n)sin(4x+nx)+1/(4-n)sin(4x-nx))+C