What is (\partial)/(\partial x)(sin(3x)cos(3y)) ?

The answer to (\partial)/(\partial x)(sin(3x)cos(3y)) is cos(3y)cos(3x)*3

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(\partial)/(\partial x)(sin(3x)cos(3y))

\frac{\partial}{\partial x} (sin (3 x) cos (3 y))

cos (3 y) cos (3 x) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x) cos (3 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (3 y) \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= cos (3 y) cos (3 x) \cdot 3

f (x) = 5 x - 3 x^{2}, at x = 1

\frac{d}{d x} (\frac{( x ^{2} - 6 ) ^{3}}{x ^{2} + 4})

\frac{d ^{2}}{d x ^{2}} (x^{\frac{9}{5}} y^{7} z^{\frac{2}{7}})

y^{^{''}} - 6 y^{^{'}} + 9 y = 6 e^{3 x}

\int cos (\frac{x}{2}) d x

What is (\partial)/(\partial x)(sin(3x)cos(3y)) ?
The answer to (\partial)/(\partial x)(sin(3x)cos(3y)) is cos(3y)cos(3x)*3