What is (d^2}{d{x}^2}({x}^{9/5)/y ^7{z}^{2/7}) ?

The answer to (d^2}{d{x}^2}({x}^{9/5)/y ^7{z}^{2/7}) is (36{y}^7{z}^{2/7})/(25{x)^{1/5}}

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(d^2}{d{x}^2}({x}^{9/5)/y ^7{z}^{2/7})

\frac{d ^{2}}{d x ^{2}} (x^{\frac{9}{5}} y^{7} z^{\frac{2}{7}})

\frac{36 y ^{7} z ^{\frac{2}{7}}}{25 x ^{\frac{1}{5}}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (x^{\frac{9}{5}} y^{7} z^{\frac{2}{7}})

\frac{d}{d x} (x^{\frac{9}{5}} y^{7} z^{\frac{2}{7}}) = \frac{9 y ^{7} z ^{\frac{2}{7}} x ^{\frac{4}{5}}}{5}

= \frac{d}{d x} (\frac{9 y ^{7} z ^{\frac{2}{7}} x ^{\frac{4}{5}}}{5})

\frac{d}{d x} (\frac{9 y ^{7} z ^{\frac{2}{7}} x ^{\frac{4}{5}}}{5}) = \frac{36 y ^{7} z ^{\frac{2}{7}}}{25 x ^{\frac{1}{5}}}

= \frac{36 y ^{7} z ^{\frac{2}{7}}}{25 x ^{\frac{1}{5}}}

y^{^{''}} - 6 y^{^{'}} + 9 y = 6 e^{3 x}

\int cos (\frac{x}{2}) d x

x \to 3 lim (4 cos (x))

x, x^{0.5}

x \to 1 - lim (\frac{( 1 )}{x - 1})

What is (d^2}{d{x}^2}({x}^{9/5)/y ^7{z}^{2/7}) ?
The answer to (d^2}{d{x}^2}({x}^{9/5)/y ^7{z}^{2/7}) is (36{y}^7{z}^{2/7})/(25{x)^{1/5}}