What is the tangent of f(x)= 1/(1-x),(2,-1) ?

The tangent of f(x)= 1/(1-x),(2,-1) is y=x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/(1-x),(2,-1)

tangent of

f (x) = \frac{1}{1 - x}, (2, - 1)

y = x - 3

Solution steps

Find the slope of

f (x) = \frac{1}{1 - x} : \frac{df ( x )}{d x} = \frac{1}{( 1 - x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{1 - x}

(2, - 1) : m = 1

Find the line with slope m=

1

and passing through

(2, - 1) : y = x - 3

y = x - 3

\frac{d ^{2}}{d x ^{2}} (e^{- x^{2}})

\frac{d}{d x} (4^{x} - e^{x} + x^{3})

x y + 2 ln (y) y^{^{'}} = 0

\int \frac{tan ^{2} ( \frac{3}{x} )}{x ^{2}} d x

e^{x} \cdot y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

What is the tangent of f(x)= 1/(1-x),(2,-1) ?
The tangent of f(x)= 1/(1-x),(2,-1) is y=x-3