What is the tangent of y=x^2-7x+7,(6,1) ?

The tangent of y=x^2-7x+7,(6,1) is y=5x-29

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tangent of y=x^2-7x+7,(6,1)

tangent of

y = x^{2} - 7 x + 7, (6, 1)

y = 5 x - 29

Solution steps

Find the slope of

y = x^{2} - 7 x + 7 : \frac{d y}{d x} = 2 x - 7

Compute the slope of

y = x^{2} - 7 x + 7

(6, 1) : m = 5

Find the line with slope m=

5

and passing through

(6, 1) : y = 5 x - 29

y = 5 x - 29

x \to π lim (e^{x})

\int x^{3} cos (h) x d x

\frac{d}{d x} (x^{2} csc (5 x))

\int 6 sin (3 x + 1) d x

x \to \frac{1}{6} lim (∣ - 6 x + 1 ∣)

What is the tangent of y=x^2-7x+7,(6,1) ?
The tangent of y=x^2-7x+7,(6,1) is y=5x-29