What is the limit as x approaches 1 of (x^2-9)/(x+3) ?

The limit as x approaches 1 of (x^2-9)/(x+3) is -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of (x^2-9)/(x+3)

x \to 1 lim (\frac{x ^{2} - 9}{x + 3})

- 2

Solution steps

x \to 1 lim (\frac{x ^{2} - 9}{x + 3})

Plug in the value

x = 1

= \frac{1 ^{2} - 9}{1 + 3}

Simplify

\frac{1 ^{2} - 9}{1 + 3} : - 2

= - 2

\frac{d}{d x} (∣ f (x) ∣)

x \to \frac{π}{4} lim (csc (x))

\int x 5 + x d x

y = 3 x^{2}

\frac{d}{d x} (x e^{\frac{- x ^{2}}{2}})

What is the limit as x approaches 1 of (x^2-9)/(x+3) ?
The limit as x approaches 1 of (x^2-9)/(x+3) is -2