What is the integral of xsec^2(x ?

The integral of xsec^2(x is (x^3sec^2(d))/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xsec^2(x

\int x sec^{2} (d) x d x

\frac{x ^{3} sec ^{2} ( d )}{3} + C

Solution steps

\int x sec^{2} (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sec^{2} (d) \cdot \int xx d x

Simplify

xx : x^{2}

= sec^{2} (d) \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= sec^{2} (d) \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{3} sec ^{2} ( d )}{3}

Add a constant to the solution

= \frac{x ^{3} sec ^{2} ( d )}{3} + C

\frac{d y}{d x}, y^{3} = x

\int e^{- 3 x} x d x

y = \frac{x + 1}{x}

x \to - 1 - lim (\frac{2}{x + 1})

x \to - \infty lim (4 + \frac{3}{x})

What is the integral of xsec^2(x ?
The integral of xsec^2(x is (x^3sec^2(d))/3+C