What is (\partial)/(\partial s)(s+2t-u) ?

The answer to (\partial)/(\partial s)(s+2t-u) is 1

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(\partial)/(\partial s)(s+2t-u)

\frac{\partial}{\partial s} (s + 2 t - u)

1

Solution steps

\frac{\partial}{\partial s} (s + 2 t - u)

Treat

t, u

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial s} (s) + \frac{\partial}{\partial s} (2 t) - \frac{\partial}{\partial s} (u)

\frac{\partial}{\partial s} (s) = 1

\frac{\partial}{\partial s} (2 t) = 0

\frac{\partial}{\partial s} (u) = 0

= 1 + 0 - 0

Simplify

= 1

\frac{d}{d x} ((x - 1) (x - 2) (x - 3))

\frac{d P}{d t} = P (3 - P) - \frac{9}{4}

\int_{3}^{8} t^{3} ln (2 t) d t

\frac{1}{9 s - 1}

x \to 0 lim (\frac{cos ( 2 x )}{x})

What is (\partial)/(\partial s)(s+2t-u) ?
The answer to (\partial)/(\partial s)(s+2t-u) is 1