What is the limit as h approaches 0 of ((1+h^3)-1)/h ?

The limit as h approaches 0 of ((1+h^3)-1)/h is 0

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limit as h approaches 0 of ((1+h^3)-1)/h

h \to 0 lim (\frac{( 1 + h ^{3} ) - 1}{h})

0

Solution steps

h \to 0 lim (\frac{1 + h ^{3} - 1}{h})

Simplify

\frac{1 + h ^{3} - 1}{h} : h^{2}

= h \to 0 lim (h^{2})

Plug in the value

h = 0

= 0^{2}

Simplify

= 0

\frac{d}{d x} (\frac{e ^{x}}{1 - e ^{2 x}})

\int \frac{56}{1 - cos ( 8 x )} d x

(- 1, 2), (4, 3)

\frac{d ^{4}}{d x ^{4}} (16 e^{x^{2}})

\frac{d}{d x} (\frac{8 x + 3}{0.2 x ^{2} + 1})

What is the limit as h approaches 0 of ((1+h^3)-1)/h ?
The limit as h approaches 0 of ((1+h^3)-1)/h is 0