What is the solution for (1-y^2)dx-xydy=0 ?

The solution for (1-y^2)dx-xydy=0 is y=(sqrt(c_{1)+x^2})/x ,y=-(sqrt(c_{1)+x^2})/x

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(1-y^2)dx-xydy=0

(1 - y^{2}) d x - x y d y = 0

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

Solution steps

(1 - y^{2}) d x - x y d y = 0

Solve separable ODE:

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

\int (x^{2} + 1)^{2} 2 x d x

y^{^{'}} = \frac{t}{y e ^{- y^{2}} + y e ^{- y^{2}} t ^{2}}

\frac{d}{d x} (- \frac{14}{x ^{4}})

\int_{- \frac{π}{2}}^{\frac{π}{2}} tan (x) d x

\frac{s}{( s ^{2} + 1 ) ^{2}}

What is the solution for (1-y^2)dx-xydy=0 ?
The solution for (1-y^2)dx-xydy=0 is y=(sqrt(c_{1)+x^2})/x ,y=-(sqrt(c_{1)+x^2})/x