What is the derivative of (((3x^2))/((2x+4)))^3 ?

The derivative of (((3x^2))/((2x+4)))^3 is (81x^5(x+4))/(2(2x+4)^2(x+2)^2)

What is the first derivative of (((3x^2))/((2x+4)))^3 ?

The first derivative of (((3x^2))/((2x+4)))^3 is (81x^5(x+4))/(2(2x+4)^2(x+2)^2)

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derivative of

(\frac{( 3 x ^{2} )}{( 2 x + 4 )})^{3}

\frac{81 x ^{5} ( x + 4 )}{2 ( 2 x + 4 ) ^{2} ( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} ((\frac{3 x ^{2}}{2 x + 4})^{3})

Apply the chain rule:

3 (\frac{3 x ^{2}}{2 x + 4})^{2} \frac{d}{d x} (\frac{3 x ^{2}}{2 x + 4})

= 3 (\frac{3 x ^{2}}{2 x + 4})^{2} \frac{d}{d x} (\frac{3 x ^{2}}{2 x + 4})

\frac{d}{d x} (\frac{3 x ^{2}}{2 x + 4}) = \frac{3 x ( x + 4 )}{2 ( x + 2 ) ^{2}}

= 3 (\frac{3 x ^{2}}{2 x + 4})^{2} \frac{3 x ( x + 4 )}{2 ( x + 2 ) ^{2}}

Simplify

3 (\frac{3 x ^{2}}{2 x + 4})^{2} \frac{3 x ( x + 4 )}{2 ( x + 2 ) ^{2}} : \frac{81 x ^{5} ( x + 4 )}{2 ( 2 x + 4 ) ^{2} ( x + 2 ) ^{2}}

= \frac{81 x ^{5} ( x + 4 )}{2 ( 2 x + 4 ) ^{2} ( x + 2 ) ^{2}}

\frac{d}{d x} ((x - x) (x + x))

\int (3 x - 4) e - x d x

\frac{\partial}{\partial x} (\frac{y ^{2}}{2})

\frac{d}{d x} (\frac{- 9 x - 1}{- 6 x + 2})

\frac{\partial}{\partial y} (40 x^{\frac{4}{5}} y^{\frac{1}{5}})

What is the derivative of (((3x^2))/((2x+4)))^3 ?
The derivative of (((3x^2))/((2x+4)))^3 is (81x^5(x+4))/(2(2x+4)^2(x+2)^2)
What is the first derivative of (((3x^2))/((2x+4)))^3 ?
The first derivative of (((3x^2))/((2x+4)))^3 is (81x^5(x+4))/(2(2x+4)^2(x+2)^2)