What is the solution for 2y^{''}+y^'-y=x+7 ?

The solution for 2y^{''}+y^'-y=x+7 is y=c_{1}e^{x/2}+c_{2}e^{-x}-x-8

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2y^{''}+y^'-y=x+7

2 y^{^{''}} + y^{^{'}} - y = x + 7

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- x} - x - 8

Solution steps

2 y^{''} (x) + y^{'} (x) - y = x + 7

Solve linear ODE:

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- x} - x - 8

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- x} - x - 8

x \to - \infty lim (x \cdot 0)

\int_{- 1}^{0} t^{\frac{1}{3}} - t^{\frac{2}{3}} d t

f (x) = - \frac{1}{4} x^{2}, (- 2, - 1)

\frac{1}{( s - 1 ) ^{3}}

\frac{d}{d x} ((8 x + e^{- x^{2}})^{3})

What is the solution for 2y^{''}+y^'-y=x+7 ?
The solution for 2y^{''}+y^'-y=x+7 is y=c_{1}e^{x/2}+c_{2}e^{-x}-x-8