What is the limit as x approaches 0 of sqrt(1+x^2) ?

The limit as x approaches 0 of sqrt(1+x^2) is 1

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limit as x approaches 0 of sqrt(1+x^2)

x \to 0 lim (1 + x^{2})

1

Solution steps

x \to 0 lim (1 + x^{2})

Plug in the value

x = 0

= 1 + 0^{2}

Simplify

= 1

f (x) = x^{7} cos (x)

y^{^{'}} = x (e + y)

x \to \infty lim (3 x^{2} - 8)

\frac{d}{d x} (2 x - \frac{1}{2} x^{2})

y^{^{'}} + e^{x} y = 12 e^{x}

What is the limit as x approaches 0 of sqrt(1+x^2) ?
The limit as x approaches 0 of sqrt(1+x^2) is 1