What is the solution for (dy)/(dx)+3y=40,y(1)=70 ?

The solution for (dy)/(dx)+3y=40,y(1)=70 is y= 40/3+(170e^{3-3x})/3

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(dy)/(dx)+3y=40,y(1)=70

\frac{d y}{d x} + 3 y = 40, y (1) = 70

y = \frac{40}{3} + \frac{170 e ^{3 - 3 x}}{3}

Solution steps

\frac{d y}{d x} + 3 y = 40

Solve linear ODE:

y = \frac{40}{3} + \frac{170 e ^{3 - 3 x}}{3}

y = \frac{40}{3} + \frac{170 e ^{3 - 3 x}}{3}

x \to (7) + lim (\frac{1}{( x - 7 ) ^{2}})

f (x) = 5 x^{2} + 7 x, at - 13

\frac{\partial}{\partial x} ((x - 1)^{2} e^{x})

\frac{d}{d x} (\frac{132}{x ^{13}})

\int_{0}^{\infty} 3 x e^{- 3 x} d x

What is the solution for (dy)/(dx)+3y=40,y(1)=70 ?
The solution for (dy)/(dx)+3y=40,y(1)=70 is y= 40/3+(170e^{3-3x})/3