What is the solution for (dy}{dx}-2/(3x)y+\frac{x^2+2)/3 y^4=0 ?

The solution for (dy}{dx}-2/(3x)y+\frac{x^2+2)/3 y^4=0 is y=\sqrt[3]{(15x^2)/(3x^5+10x^3+c_{1)}}

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(dy}{dx}-2/(3x)y+\frac{x^2+2)/3 y^4=0

\frac{d y}{d x} - \frac{2}{3 x} y + \frac{x ^{2} + 2}{3} y^{4} = 0

Solution steps

\frac{d y}{d x} - \frac{2}{3 x} y + \frac{x ^{2} + 2}{3} y^{4} = 0

Solve Bernoulli ODE:

\int x \cdot ln (2 x) d x

y^{^{'}} = y (1 - 0.0004 y)

x = 4 y^{2}, x = 8 + 2 y^{2}

\frac{d}{d x} (3 x^{2} e^{x^{3}})

t^{2} y^{^{'}} + 2 t y = 3

What is the solution for (dy}{dx}-2/(3x)y+\frac{x^2+2)/3 y^4=0 ?
The solution for (dy}{dx}-2/(3x)y+\frac{x^2+2)/3 y^4=0 is y=\sqrt[3]{(15x^2)/(3x^5+10x^3+c_{1)}}