What is the derivative of 2x^3-21x^2+60x ?

The derivative of 2x^3-21x^2+60x is 6x^2-42x+60

What is the first derivative of 2x^3-21x^2+60x ?

The first derivative of 2x^3-21x^2+60x is 6x^2-42x+60

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\frac{d}{d x} (2 x^{3} - 21 x^{2} + 60 x)

6 x^{2} - 42 x + 60

Solution steps

\frac{d}{d x} (2 x^{3} - 21 x^{2} + 60 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (21 x^{2}) + \frac{d}{d x} (60 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (21 x^{2}) = 42 x

\frac{d}{d x} (60 x) = 60

= 6 x^{2} - 42 x + 60

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What is the derivative of 2x^3-21x^2+60x ?
The derivative of 2x^3-21x^2+60x is 6x^2-42x+60
What is the first derivative of 2x^3-21x^2+60x ?
The first derivative of 2x^3-21x^2+60x is 6x^2-42x+60