What is the limit as x approaches 1+of (4x-3)/(x-1) ?

The limit as x approaches 1+of (4x-3)/(x-1) is infinity

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limit as x approaches 1+of (4x-3)/(x-1)

x \to 1 + lim (\frac{4 x - 3}{x - 1})

\infty

Solution steps

x \to 1 + lim (\frac{4 x - 3}{x - 1})

\frac{4 x - 3}{x - 1} = (4 x - 3) \frac{1}{x - 1}

= x \to 1 + lim ((4 x - 3) \frac{1}{x - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 + lim (4 x - 3) \cdot x \to 1 + lim (\frac{1}{x - 1})

x \to 1 + lim (4 x - 3) = 1

x \to 1 + lim (\frac{1}{x - 1}) = \infty

= 1 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

f (x) = ln (- x)

\frac{d}{d x} (x^{7} + \frac{1}{x ^{7}} + 7 x + \frac{7}{x} + 7)

\frac{\partial}{\partial x} (b x)

\frac{d y}{d t} - 2 y = e^{2 t}

\frac{\partial}{\partial x} (x z ln (x + y + z))

What is the limit as x approaches 1+of (4x-3)/(x-1) ?
The limit as x approaches 1+of (4x-3)/(x-1) is infinity