What is the derivative of arctan(sqrt(x)) ?

The derivative of arctan(sqrt(x)) is 1/(2sqrt(x)(x+1))

What is the first derivative of arctan(sqrt(x)) ?

The first derivative of arctan(sqrt(x)) is 1/(2sqrt(x)(x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arctan (x)

\frac{1}{2 x ( x + 1 )}

Solution steps

\frac{d}{d x} (arctan (x))

Apply the chain rule:

\frac{1}{( x ) ^{2} + 1} \frac{d}{d x} (x)

= \frac{1}{( x ) ^{2} + 1} \frac{d}{d x} (x)

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{( x ) ^{2} + 1} \cdot \frac{1}{2 x}

Simplify

\frac{1}{( x ) ^{2} + 1} \cdot \frac{1}{2 x} : \frac{1}{2 x ( x + 1 )}

= \frac{1}{2 x ( x + 1 )}

n = 1 \sum \infty \frac{n}{n}

f (x) = 4^{x} x^{4}

\frac{e ^{- 2 s}}{s - 2}

\int \frac{1}{( x ^{2} 4 - x ^{2} )} d x

\int y^{\frac{1}{2}} d y

What is the derivative of arctan(sqrt(x)) ?
The derivative of arctan(sqrt(x)) is 1/(2sqrt(x)(x+1))
What is the first derivative of arctan(sqrt(x)) ?
The first derivative of arctan(sqrt(x)) is 1/(2sqrt(x)(x+1))