What is the derivative of (6x^2+4x)^2 ?

The derivative of (6x^2+4x)^2 is 2(6x^2+4x)(12x+4)

What is the first derivative of (6x^2+4x)^2 ?

The first derivative of (6x^2+4x)^2 is 2(6x^2+4x)(12x+4)

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derivative of

(6 x^{2} + 4 x)^{2}

2 (6 x^{2} + 4 x) (12 x + 4)

Solution steps

\frac{d}{d x} ((6 x^{2} + 4 x)^{2})

Apply the chain rule:

2 (6 x^{2} + 4 x) \frac{d}{d x} (6 x^{2} + 4 x)

= 2 (6 x^{2} + 4 x) \frac{d}{d x} (6 x^{2} + 4 x)

\frac{d}{d x} (6 x^{2} + 4 x) = 12 x + 4

= 2 (6 x^{2} + 4 x) (12 x + 4)

\frac{\partial}{\partial y} (\frac{x - y}{x ^{2} + y ^{2}})

3 e^{t}

\int csc^{2} (θ) d θ

f (θ) = cot (θ)

\int \frac{1}{u ^{2} + 4} d u

What is the derivative of (6x^2+4x)^2 ?
The derivative of (6x^2+4x)^2 is 2(6x^2+4x)(12x+4)
What is the first derivative of (6x^2+4x)^2 ?
The first derivative of (6x^2+4x)^2 is 2(6x^2+4x)(12x+4)