What is inverse oflaplace 2/(s-3) ?

The answer to inverse oflaplace 2/(s-3) is 2e^{3t}

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inverse oflaplace 2/(s-3)

inverse laplace

\frac{2}{s - 3}

2 e^{3 t}

Solution steps

L^{- 1} {\frac{2}{s - 3}}

= L^{- 1} {2 \cdot \frac{1}{s - 3}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{1}{s - 3}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 3}} = e^{3 t}

= 2 e^{3 t}

f (x) = x^{2} + 2, (5, 27)

10 sin (x) cos (x)

\frac{d y}{d x}, y = 3 x^{2}

\frac{\partial}{\partial x} (- (x^{2} + y^{2}))

ln (x e^{- 8 x})

What is inverse oflaplace 2/(s-3) ?
The answer to inverse oflaplace 2/(s-3) is 2e^{3t}