What is the integral of (1+x)sqrt(x) ?

The integral of (1+x)sqrt(x) is 2/3 x^{3/2}+2/5 x^{5/2}+C

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integral of (1+x)sqrt(x)

\int (1 + x) x d x

\frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int (1 + x) x d x

Expand

(1 + x) x : x + x^{\frac{3}{2}}

= \int x + x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int x^{\frac{3}{2}} d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

= \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

f (x) = 9 e^{x} cos (x), (0, 9)

y^{^{''}} + y = x^{3}

\int_{0}^{y} y e^{- y} d y

\frac{d y}{d t} y = (2 t - 1) (3 t - 4)^{- 1}

lo g_{5} (2 x)

What is the integral of (1+x)sqrt(x) ?
The integral of (1+x)sqrt(x) is 2/3 x^{3/2}+2/5 x^{5/2}+C