What is inverse oflaplace 4/(s+2) ?

The answer to inverse oflaplace 4/(s+2) is 4e^{-2t}

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inverse oflaplace 4/(s+2)

inverse laplace

\frac{4}{s + 2}

4 e^{- 2 t}

Solution steps

L^{- 1} {\frac{4}{s + 2}}

= L^{- 1} {4 \cdot \frac{1}{s + 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s + 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 2}} = e^{- 2 t}

= 4 e^{- 2 t}

\int \frac{2000}{1 + 0.3 e ^{- 0.276 t}} d t

\frac{\partial}{\partial x} ((x yz)^{\frac{1}{2}})

\int (5 x^{2} - 3) (2 x) d x

\int (7 x + 6)^{4} d x

\frac{\partial}{\partial y} (2 x + y e^{x y})

What is inverse oflaplace 4/(s+2) ?
The answer to inverse oflaplace 4/(s+2) is 4e^{-2t}