What is the derivative of (16/x) ?

The derivative of (16/x) is -(16)/(x^2)

What is the first derivative of (16/x) ?

The first derivative of (16/x) is -(16)/(x^2)

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\frac{d}{d x} (\frac{16}{x})

- \frac{16}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{16}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 1 \cdot x^{- 1 - 1})

Simplify

16 (- 1 \cdot x^{- 1 - 1}) : - \frac{16}{x ^{2}}

= - \frac{16}{x ^{2}}

y^{^{''}} - 3 y^{^{'}} = - 9

\int \frac{x ^{3}}{25 - x ^{2}} d x

\int_{0}^{2} 3 y 4 - y^{2} d y

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 3

x \frac{d y}{d x} - 2 y = x^{2}

What is the derivative of (16/x) ?
The derivative of (16/x) is -(16)/(x^2)
What is the first derivative of (16/x) ?
The first derivative of (16/x) is -(16)/(x^2)