What is the solution for y^'=(2-3y)/(200+x) ?

The solution for y^'=(2-3y)/(200+x) is y=-(c_{1})/(3(8000000+120000x+600x^2+x^3))+2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(2-3y)/(200+x)

y^{^{'}} = \frac{2 - 3 y}{200 + x}

y = - \frac{c _{1}}{3 ( 8000000 + 120000 x + 600 x ^{2} + x ^{3} )} + \frac{2}{3}

Solution steps

y^{'} (x) = \frac{2 - 3 y}{200 + x}

Solve separable ODE:

y = - \frac{c _{1}}{3 ( 8000000 + 120000 x + 600 x ^{2} + x ^{3} )} + \frac{2}{3}

y = - \frac{c _{1}}{3 ( 8000000 + 120000 x + 600 x ^{2} + x ^{3} )} + \frac{2}{3}

y^{^{''}} + 2 y^{^{'}} = sin (t)

f (x) = - \frac{1}{2} (x^{- 2} - x^{4})

\int sin (2 x) \cdot cos (2 x) d x

n = 1 \sum \infty \frac{1}{n} x^{n}

n = 1 \sum \infty (\frac{6}{4})^{n}

What is the solution for y^'=(2-3y)/(200+x) ?
The solution for y^'=(2-3y)/(200+x) is y=-(c_{1})/(3(8000000+120000x+600x^2+x^3))+2/3