What is (\partial)/(\partial x)(sin(4x-7y)) ?

The answer to (\partial)/(\partial x)(sin(4x-7y)) is cos(4x-7y)*4

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(\partial)/(\partial x)(sin(4x-7y))

\frac{\partial}{\partial x} (sin (4 x - 7 y))

cos (4 x - 7 y) \cdot 4

Solution steps

\frac{\partial}{\partial x} (sin (4 x - 7 y))

Treat

y

as a constant

Apply the chain rule:

cos (4 x - 7 y) \frac{\partial}{\partial x} (4 x - 7 y)

= cos (4 x - 7 y) \frac{\partial}{\partial x} (4 x - 7 y)

\frac{\partial}{\partial x} (4 x - 7 y) = 4

= cos (4 x - 7 y) \cdot 4

\frac{( x + 1 ) d y}{d x} = - y + 10

\frac{d}{d x} (x^{2} + 45)

x \to \infty lim (8, x)

\int_{0}^{\frac{π}{2}} (sin (x))^{5} d x

\frac{d y}{d x} - y = \frac{11}{8} e^{- \frac{x}{3}}

What is (\partial)/(\partial x)(sin(4x-7y)) ?
The answer to (\partial)/(\partial x)(sin(4x-7y)) is cos(4x-7y)*4