What is the tangent of y=(1+2x)^2,(2,25) ?

The tangent of y=(1+2x)^2,(2,25) is y=20x-15

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tangent of y=(1+2x)^2,(2,25)

tangent of

y = (1 + 2 x)^{2}, (2, 25)

y = 20 x - 15

Solution steps

Find the slope of

y = (1 + 2 x)^{2} : \frac{d y}{d x} = 4 (1 + 2 x)

Compute the slope of

y = (1 + 2 x)^{2}

(2, 25) : m = 20

Find the line with slope m=

20

and passing through

(2, 25) : y = 20 x - 15

y = 20 x - 15

y^{^{''}} + y^{^{'}} - 2 y = 1 - 2 x^{2}

t \to 1 lim (sin (π t))

\frac{d}{d j} (3 i + 2 j)

\int_{0}^{1} x (1 - x) sin (nπ x) d x

What is the tangent of y=(1+2x)^2,(2,25) ?
The tangent of y=(1+2x)^2,(2,25) is y=20x-15