What is the tangent of y=4x^4+3x-5,(1,2) ?

The tangent of y=4x^4+3x-5,(1,2) is y=19x-17

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tangent of y=4x^4+3x-5,(1,2)

tangent of

y = 4 x^{4} + 3 x - 5, (1, 2)

y = 19 x - 17

Solution steps

Find the slope of

y = 4 x^{4} + 3 x - 5 : \frac{d y}{d x} = 16 x^{3} + 3

Compute the slope of

y = 4 x^{4} + 3 x - 5

(1, 2) : m = 19

Find the line with slope m=

19

and passing through

(1, 2) : y = 19 x - 17

y = 19 x - 17

f (x) = \frac{1}{2 + 3 x}, at x = 1

y = - 3 x - 5

\frac{\partial}{\partial x} (- 2 (y + 1) x^{- 3})

sin^{2} (x) - cos^{2} (x)

2 sin (x) y^{^{'}} + y cos (x) = y^{2} cos (x)

What is the tangent of y=4x^4+3x-5,(1,2) ?
The tangent of y=4x^4+3x-5,(1,2) is y=19x-17