What is the solution for (dy)/(dx)=y^{-1}x^{-3} ?

The solution for (dy)/(dx)=y^{-1}x^{-3} is y=(sqrt(2c_{1)x^2-1})/x ,y=-(sqrt(2c_{1)x^2-1})/x

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(dy)/(dx)=y^{-1}x^{-3}

\frac{d y}{d x} = y^{- 1} x^{- 3}

y = \frac{2 c _{1} x ^{2} - 1}{x}, y = - \frac{2 c _{1} x ^{2} - 1}{x}

Solution steps

\frac{d y}{d x} = y^{- 1} x^{- 3}

Solve separable ODE:

y = \frac{2 c _{1} x ^{2} - 1}{x}, y = - \frac{2 c _{1} x ^{2} - 1}{x}

y = \frac{2 c _{1} x ^{2} - 1}{x}, y = - \frac{2 c _{1} x ^{2} - 1}{x}

y^{^{'}} = \frac{6 y ^{2}}{x ^{2}}, y (- 2) = 5

\frac{d}{d x} (\frac{4}{3} tan (x))

x \to - 1 lim (13 + x)

\frac{d x}{d t} = \frac{x ^{2} + t t ^{2} + x ^{2}}{t x}

\frac{d}{d x} (\frac{x ^{2}}{4 + x})

What is the solution for (dy)/(dx)=y^{-1}x^{-3} ?
The solution for (dy)/(dx)=y^{-1}x^{-3} is y=(sqrt(2c_{1)x^2-1})/x ,y=-(sqrt(2c_{1)x^2-1})/x