What is (\partial)/(\partial x)(-xy-x^2) ?

The answer to (\partial)/(\partial x)(-xy-x^2) is -y-2x

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(\partial)/(\partial x)(-xy-x^2)

\frac{\partial}{\partial x} (- x y - x^{2})

- y - 2 x

Solution steps

\frac{\partial}{\partial x} (- x y - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x^{2}) = 2 x

= - y - 2 x

4 x + 3

\int \frac{cos ( x )}{sin ^{10} ( x )} d x

\int 4 t^{2} + 4 d t

\int sin (2 x + π) d x

\frac{d y}{d x} = \frac{e ^{x} - y}{x}

What is (\partial)/(\partial x)(-xy-x^2) ?
The answer to (\partial)/(\partial x)(-xy-x^2) is -y-2x