What is the derivative of f(x)=x-2cos(x) ?

The derivative of f(x)=x-2cos(x) is 1+2sin(x)

What is the first derivative of f(x)=x-2cos(x) ?

The first derivative of f(x)=x-2cos(x) is 1+2sin(x)

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derivative of

f (x) = x - 2 cos (x)

1 + 2 sin (x)

Solution steps

\frac{d}{d x} (x - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2 cos (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 1 - (- 2 sin (x))

Simplify

= 1 + 2 sin (x)

\frac{1 - 6 t}{3 + t}

x \to 0 + lim (\frac{1}{x} + ln (x))

(x^{2} + 2 y^{2}) d x = - x y d y

\int x ln (2 x) d x

\frac{sec ( x )}{x}

What is the derivative of f(x)=x-2cos(x) ?
The derivative of f(x)=x-2cos(x) is 1+2sin(x)
What is the first derivative of f(x)=x-2cos(x) ?
The first derivative of f(x)=x-2cos(x) is 1+2sin(x)