What is the derivative of x^2-5x ?

The derivative of x^2-5x is 2x-5

What is the first derivative of x^2-5x ?

The first derivative of x^2-5x is 2x-5

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derivative of

x^{2} - 5 x

2 x - 5

Solution steps

\frac{d}{d x} (x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

= 2 x - 5

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{1 + e}

\int 1 + x d x

\int x^{5} (1 + x^{3})^{\frac{3}{2}} d x

y^{^{'}} = 8 y^{2} + x y^{2}, y (0) = 1

4 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{5} (t)